A) \[{{C}_{2}}{{H}_{6}}\]
B) \[{{C}_{2}}{{H}_{5}}Cl\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{5}}OC{{H}_{3}}\]
Correct Answer: C
Solution :
Cold alkaline potassium permanganate solution (1% alkaline \[\text{KMn}{{\text{O}}_{\text{4}}}\]or Baeyers reagent) is decolourised in presence of unsaturation only. In the given compounds only ethylene is unsaturated compound. So, it decolourise Baeyers reagent as : \[2KMn{{O}_{4}}2KOH\xrightarrow{{}}2{{K}_{2}}Mn{{O}_{4}}+\underbrace{{{H}_{2}}O+[O]}_{{}}\] \[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{2}}OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}OH\] Ethylene glycol (Colourless)
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