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EAMCET Medical EAMCET Medical Solved Paper-2004

  • question_answer
    The first ionisation potentials of four consecutive elements, present in the second period of the periodic table, are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which one of the following is the first ionisation potential (in eV) of nitrogen?

    A)  13.6                                      

    B)  11.2

    C)  8.3                                        

    D)  14.5

    Correct Answer: D

    Solution :

                     Elements in the 2nd period are: Period                                   Elements II nd                                       \[\text{Li Be BC N O F Ne}\] In a period from left to right, ionization potential increases. But in case of nitrogen and oxygen, nitrogen has more ionization potential than oxygen atom due to stable electronic configuration of nitrogen. \[{{\,}_{7}}N=1{{s}^{2}},2{{s}^{2}}2{{p}^{3}}\]
    \[\uparrow \] \[\uparrow \] \[\uparrow \]
    (Stable configuration) \[{{\,}_{8}}O=1{{s}^{2}},2{{s}^{2}}2{{p}^{4}}\]  (Unstable configuration) Nitrogen has stable configuration as the p-orbitals are half-filled completely. So, more energy is required to remove an electron from the outermost orbit of nitrogen atom. So, \[{{\text{N}}_{\text{2}}}\] has 14.5 value of ionisation potential.


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