A) 750
B) 7.5
C) 0.075
D) 0.75
Correct Answer: D
Solution :
\[\because \] 250 mL of solution contains oxalic acid = 6.3g \[\therefore \] 1000 mL (1 L) of solution contains oxalic \[acid\,=\frac{6.3}{250}\times 1000\] \[=25.2\,g/L\] or Strength = 25.2 / L \[S=E\times N\] where, S = strength E = Equivalent wt. N = Normality \[\text{Eq}\text{.}\,\text{wt}\text{. = }\frac{\text{Molecular}\,\text{wt}\text{.}}{\text{basicity}\,\text{of}\,\text{acid}}\] Molecular wt. of oxalic acid = 126 Basicity =2 \[=\frac{126}{2}=63\] So, \[S=E\times N\] \[25.2=63\times N\] \[N=\frac{25.2}{63}=0.4\] Hence, the given solution is 250 mL 0.4 N, oxalic acid solution. Now, this solution is makes to 0.1 N solution as: \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[0.4\times 250=0.1\times {{V}_{2}}\] \[{{V}_{2}}=\frac{0.4\times 250}{0.1}=1000\,mL\] So, water added = 1000 - 250 = 750 mL water = 0.75 L water
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