A) \[2{{F}_{2}}+4NaOH\to 4NaF+2{{H}_{2}}O\]
B) \[3{{F}_{2}}+NaOH\to 5NaF+NaF{{O}_{3}}\]
C) \[{{F}_{2}}+2NaOH\to NaF+NaOF+{{H}_{2}}O\]
D) \[2{{F}_{2}}+2NaOH\to 2NaF+O{{F}_{2}}+{{H}_{2}}O\]
Correct Answer: D
Solution :
This is the correct relation for first order reaction. Reaction of fluorine with \[\text{NaOH}\] takes place in two conditions as: In cold \[\text{ }\!\!~\!\!\text{ NaOH}\] \[\text{2}{{\text{F}}_{2}}+2NaOH\xrightarrow{{}}2NaF+O{{F}_{2}}+{{H}_{2}}O\] In hot \[\text{NaOH}\] \[{{F}_{2}}+NaOH\xrightarrow{{}}NaF+{{O}_{2\text{ }}}+{{H}_{2}}O\]
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