A) 27
B) 64
C) 125
D) 216
Correct Answer: B
Solution :
Radius of nucleus \[=K{{[A]}^{1/3}}\]where, A = mass number \[5.6=1.4\times {{[A]}^{1/3}}\] \[{{A}^{1/3}}=\frac{5.6}{1.4}=4\] \[A={{4}^{3}}\] \[A=64\]
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