A) \[C{{H}_{3}}\]
B) \[{{C}_{4}}{{H}_{9}}\]
C) \[CH\]
D) \[{{C}_{3}}{{H}_{g}}\]
Correct Answer: D
Solution :
% of carbon in compound \[=\frac{12}{44}\times \frac{\text{weight of C}{{\text{O}}_{\text{2}}}}{\text{weight of comp}\text{.}}\times 100\] \[=\frac{12}{44}\times \frac{12}{4}\times 100\] \[=81.81%\] % of \[H=100-81.81=18.19%\]Element | \[\frac{\text{percentage}}{\text{at}\text{. wt}\text{.}}\] | Simple ratio |
C | \[\frac{81.81}{12}=6.81\] | \[\frac{6.81}{6.81}=1.0\times 3=3\] |
H | \[\frac{18.19}{1}=18.19\] | \[\frac{18.19}{6.81}=2.67\times 3=8\] |
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