A) 108 F
B) \[\frac{108}{F}\]
C) \[\frac{F}{108}\]
D) \[\frac{1}{108\,F}\]
Correct Answer: B
Solution :
Electrochemical equivalent\[(z)=\frac{E}{F}\]\[=\frac{108}{\text{F}}\text{g}\text{.Coulom}{{\text{b}}^{-1}}\]You need to login to perform this action.
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