A) 2t
B) \[\frac{t}{30}\]
C) \[120t\]
D) \[60t\]
Correct Answer: A
Solution :
For first order reaction, \[k=\frac{2.303}{{{t}_{1}}}\log \frac{100}{100-90}=\frac{2.303}{{{t}_{2}}}\log \frac{100}{100-99}\] \[\therefore \] \[\frac{1}{t}\log 10=\frac{1}{{{t}_{2}}}\log 100\] or, \[\frac{1}{t}=\frac{1}{{{t}_{2}}}\times 2\] \[{{t}_{2}}=2t\,s\]You need to login to perform this action.
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