A) \[\frac{E}{2}\]
B) \[\frac{E}{3}\]
C) \[\frac{E}{4}\]
D) zero
Correct Answer: C
Solution :
Let capacitance of a parallel plate capacitor\[{{C}_{1}}=C\] If energy stored in capacitor \[{{C}_{1}}\]is E. The charge on capacitor \[q=\sqrt{2EC}\] \[\left( \because E=\frac{1}{2}\frac{{{q}^{2}}}{C} \right)\] When. another uncharged capacitor \[{{C}_{2}}\]having same capacitance C is connected to it then total charge on both capacitor = q When disconnected, the charge on each one capacitor \[q=\frac{q}{2}=\frac{\sqrt{2EC}}{2}=\sqrt{\frac{EC}{2}}\] \[\therefore \] Energy stored in\[{{C}_{2}}\] \[E=\frac{1}{2}\frac{q{{}^{2}}}{C}\] \[=\frac{1}{2}\frac{EC}{2}\frac{1}{C}\] \[E=\frac{E}{4}\]
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