A) 14
B) 25
C) 28
D) 50
Correct Answer: D
Solution :
Thermo emf of iron-platinum thermo couple \[{{e}_{1}}=1600\mu V\] Thermo emf of constant-platinum thermocouple \[{{e}_{2}}=-3400\mu V\] Thermo emfofiron-constatan thermocouple for the same range of temperature \[={{e}_{3}}\] According to law of intermediate temperatures. For the same range of temperature, \[em{{f}_{iron-cons\tan \tan }}=em{{f}_{iron-platinum}}\] \[+em{{p}_{pletinum-cons\tan \tan }}\] \[em{{f}_{iron-cons\tan \tan }}=em{{f}_{iron-platinum}}\] \[-em{{p}_{cons\tan \tan -platinum}}\] \[=1600\mu V-(-3400\mu V)\] \[1600\mu V+3400\mu V\] \[em{{f}_{iron-cons\tan \tan }}=5000\mu V\] \[\therefore \]Thermo emf of iron-constantan thermocouple per \[{{C}^{o}}=\frac{5000\mu V}{100{{\,}^{o}}C}\] \[=50\mu {{V}^{o}}{{C}^{-1}}\]
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