A) 8.44
B) 84.4
C) 844
D) 8440
Correct Answer: B
Solution :
The frequency of oscillation of L-C circuit is given by \[f=\frac{1}{2\pi \sqrt{LC}}\] or \[LC=\frac{1}{4{{\pi }^{2}}{{f}^{2}}}\] \[L=\frac{1}{4{{\pi }^{2}}{{f}^{2}}C}\] Here, \[f=1MHz=1\times {{10}^{6}}Hz,\] \[C=0.3pF=0.3\times {{10}^{-12}}F\] \[\therefore \] \[L=\frac{1}{4\times \frac{22}{7}\times \frac{22}{7}\times {{({{10}^{6}})}^{2}}\times 0.3\times {{10}^{-12}}}H\] \[L=\frac{490}{4\times 484\times 3\times {{10}^{12}}\times {{10}^{-12}}}H\] \[L=0.0844\,H\] \[L=874.4\,mH\]
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