A) \[{{C}_{2}}{{H}_{5}}OH,\text{ }{{C}_{2}}{{H}_{4}}\]
B) \[C{{H}_{3}}C{{O}_{2}}H,{{(C{{H}_{3}}CO)}_{2}}O\]
C) \[C{{H}_{3}}C{{O}_{2}}H,C{{H}_{3}}C{{O}_{2}}C{{H}_{3}}\]
D) \[{{C}_{2}}{{H}_{5}}OH,C{{H}_{3}}C{{O}_{2}}H\]
Correct Answer: B
Solution :
\[\text{HN}{{\text{O}}_{\text{3}}}\] is an oxidising agent. It oxidises aldehyde into acid. \[{{P}_{4}}{{O}_{10}}\] (dehydratingagent) dehydrates the acid into anhydride. Hence, reaction is as follows : \[C{{H}_{3}}CHO\xrightarrow{HN{{O}_{3}}}\underset{(x)}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow{P & 4{{O}_{10}}}\] \[\underset{(Y)}{\mathop{(C{{H}_{3}}C{{O}_{2}})}}\,O\]
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