A) Sodium
B) Dry silver oxide
C) Ethyl chloride
D) Dry silver powder
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{5}}OK+{{C}_{2}}{{H}_{5}}I\xrightarrow{\Delta }\underset{\text{diethyl}\,\text{ether}}{\mathop{{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}}}\,+KI\] This is Williamsons synthesis of ether. Ether can also be prepared by the action of dry silver oxide on ethyl bromide. \[2{{C}_{2}}{{H}_{5}}Br+A{{g}_{2}}O\xrightarrow{\Delta }{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]\[+2AgBr\]
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