A) \[\frac{5hcR}{36}\]
B) \[\frac{4hcR}{3}\]
C) \[\frac{3hcR}{4}\]
D) \[\frac{7hcR}{144}\]
Correct Answer: C
Solution :
We know that, \[\Delta E=hc.R\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] For lowest energy, spectral line in Lyman series, \[{{n}_{1}}=1,{{n}_{2}}=2.\] Hence, \[\Delta E=hc.R\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right]\] \[\Delta E=\frac{3hcR}{4}\]
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