A) \[sp,sp\]
B) \[s{{p}^{3}},s{{p}^{3}}\]
C) \[s{{p}^{2}},s{{p}^{2}}\]
D) \[s{{p}^{3}},s{{p}^{2}}\]
Correct Answer: A
Solution :
Alkyl halides give elimination reaction with alcoholic KOH and yield an alkene or alkyne (From dihalides) e.g., \[\underset{1,-2\text{dibromo}\,\text{ethane}}{\mathop{Br-C{{H}_{2}}-C{{H}_{2}}-Br}}\,\xrightarrow[\Delta ]{alc.KOH}\underset{acetylene}{\mathop{\overset{sp}{\mathop{CH}}\,\equiv C\overset{sp}{\mathop{H}}\,}}\,\] Hence, product has both carbon sp- hybrid.
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