A) aqueous KF
B) aqueous HF
C) molten \[\text{KH}{{\text{F}}_{\text{2}}}\]
D) \[\text{N}{{\text{H}}_{\text{4}}}\text{F}\]
Correct Answer: C
Solution :
In Whytlaw-Gray method fluorine is obtained by electrolysis of molten \[\text{KH}{{\text{F}}_{\text{2}}}\]in a cell made of \[\text{Cu,Ni}\]or monel-metal. \[2KH{{F}_{2}}2{{K}^{+}}2{{H}^{+}}+4{{F}^{-}}\]\[4{{F}^{-}}\xrightarrow{{}}2{{F}_{2}}+4{{e}^{-}}\]
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