A) \[KN{{O}_{2}},{{C}_{2}}{{H}_{5}}OH,\text{ }{{H}_{2}}O,\text{ }\Delta \]
B) \[NaN{{O}_{2}},HCl,0{{\,}^{o}}C\]
C) \[KCN,{{H}_{2}}O,\Delta \]
D) \[AgN{{O}_{2}},{{C}_{2}}{{H}_{5}}OH,{{H}_{2}}O,\Delta \]
Correct Answer: A
Solution :
Potassium nitrite converts ethyl chloride into ethyl nitrite. \[{{C}_{2}}{{H}_{5}}KN{{O}_{2}}\xrightarrow[\Delta ]{{{C}_{2}}{{H}_{5}}OH}\underset{\text{ethyl}\,\text{nitrite}}{\mathop{{{C}_{2}}{{H}_{5}}ONO}}\,\] \[+KCl\]
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