A) lone pair-lone pair repulsion
B) lone pair-bond pair repulsion
C) bond pair-bond pair repulsion
D) high electronegativity of oxygen
Correct Answer: A
Solution :
The hybridisation of oxygen in water molecule is \[s{{p}^{3}}.\] So water must be tetrahedral and have bond angle \[\text{10}{{\text{9}}^{\text{o}}}\text{28 }\!\!\!\!\text{ }\text{.}\] But due to the presence of two lone pair of electrons on oxygen atom (repulsion between lone pair-lone pair) the bond angle decreases about \[\text{104}\text{.}{{\text{5}}^{\text{o}}}\] and the geometry becomes distorted tetrahedral or V-shapedYou need to login to perform this action.
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