A) \[\frac{M{{v}^{2}}(\gamma -1)}{2RJ}\]
B) \[\frac{m}{M}\frac{{{v}^{2}}(\gamma -1)}{2RJ}\]
C) \[\frac{m{{v}^{2}}\gamma }{2RJ}\]
D) \[\frac{M{{v}^{2}}\gamma }{2RJ}\]
Correct Answer: A
Solution :
\[\Delta U=\frac{\mu RJ\Delta \Tau }{(\gamma -1)}\] \[\Rightarrow \] \[\Delta T=\frac{(\gamma -1)\Delta U}{\mu RJ}\] \[\Rightarrow \] \[\Delta T=\frac{(\gamma -1)\times \frac{1}{2}m{{v}^{2}}}{(m/M)RJ}\] \[=\frac{M(\gamma -1){{v}^{2}}}{2RJ}=\frac{M{{v}^{2}}(\gamma -1)}{2RJ}\]You need to login to perform this action.
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