A) \[<10\]
B) >20
C) Between 10 and 20
D) <5
Correct Answer: A
Solution :
\[{{V}_{s}}=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{q}{R}\] \[\therefore \] \[500=\frac{9\times {{10}^{9}}\times 3\times {{10}^{-6}}}{R}\] \[\Rightarrow \] \[R=\frac{9\times {{10}^{9}}\times 3\times {{10}^{-6}}}{500}\] \[\Rightarrow \] \[R=54\,\,m\] \[\therefore \] Electric field on the surface \[{{E}_{s}}=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{q}{{{R}^{2}}}\] \[=\frac{{{V}_{S}}}{R}=\frac{500}{54}=9.25<10\,N{{C}^{-1}}\]You need to login to perform this action.
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