A) 50
B) 40
C) 30
D) 20
Correct Answer: B
Solution :
The projectile of the body is shown in the figure. In the upward journey, the body is at A at t = 1 s and in downward journey it is at A at t = 7 s. Hence, we can conclude that during upward journey, the body will be at \[\beta \] at t = 4 s. Thus, \[v=u-gt\] \[0=u-10\times 4\] \[(\because \,v=0)\] \[\therefore \] \[u=40\,m/s.\]You need to login to perform this action.
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