A) \[3\times {{10}^{-3}}\]
B) \[9\times {{10}^{-3}}\]
C) \[{{10}^{-3}}\]
D) \[1.5\times {{10}^{-3}}\]
Correct Answer: B
Solution :
The rationalised rate =\[\frac{-d[A]}{dt}=-\frac{1}{3}\frac{d[B]}{dt}=\frac{1}{2}\frac{d[C]}{dt}\] From this relation we have \[\frac{-d[B]}{dt}=-3\times \frac{d[A]}{dt}\]\[=-3\times 3\times {{10}^{-3}}=9\times {{10}^{-3}}\]You need to login to perform this action.
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