A) 300
B) 600
C) 900
D) 200
Correct Answer: C
Solution :
Molarity of glucose solution\[=\frac{0.5g}{180\times 1L}=0.0027\,M\] Isotonic solution have equal molar concentrations, hence, molarity of organic compound solution = 0.0027 M \[\therefore \] Molecular weight of compound\[=\frac{2.5}{0.0027\times 1}=900\]You need to login to perform this action.
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