A) 1.40
B) 2.65
C) 1.85
D) 2.15
Correct Answer: C
Solution :
For a body centered cubic lattice radius (r) \[=\frac{\sqrt{3}}{4}a=0.433\,a\] Therefore, radius of \[\text{N}{{\text{a}}^{\text{+}}}\] \[=0.433\times 4.29=1.8575\]You need to login to perform this action.
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