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EAMCET Medical EAMCET Medical Solved Paper-2007

  • question_answer
    A ball of mass 0.6 kg attached to a light inextensible string rotates in a vertical circle of radius 0.75 m such that it has a speed of \[5\text{ }m{{s}^{-1}}\] when the string is horizontal. Tension in string when it h horizontal on other side is \[(g=10m{{s}^{-}}2)\]

    A)  30 N                                     

    B)  26 N

    C)  20 N                                     

    D)  6 N

    Correct Answer: C

    Solution :

                     Tension in the string when it makes angle \[\theta \] with the vertical, \[T=\frac{m{{v}^{2}}}{r}+mg\cos \theta \] When the string is horizontal, \[\theta ={{90}^{o}}\] Here, m = 0.6 kg, r = 0.75 m, v = 5 m/ s Hence,   \[T=\frac{m{{v}^{2}}}{r}+mg\times 0=\frac{m{{v}^{2}}}{r}\] \[\therefore \]  \[T=\frac{0.6\times {{(5)}^{2}}}{0.75}=20\,N\]


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