A) \[12\times {{10}^{3}}J\]
B) \[25\times {{10}^{-3}}J\]
C) \[0.48\times {{10}^{-3}}J\]
D) \[0.24\times {{10}^{-3}}J\]
Correct Answer: C
Solution :
Equation of SHM \[Y=3\sin (0.2t)\] Comparing with \[Y=a\sin \omega t,\]we have \[a=3m,\,\omega =0.2\,{{s}^{-1}}\] Mass of the particle \[=3g=3\times {{10}^{-3}}\,kg\] Therefore, kinetic energy of the particle is \[K=\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{x}^{2}})\]\[=\frac{1}{2}\times 3\times {{10}^{-3}}\times {{(0.2)}^{2}}({{3}^{2}}-{{1}^{2}})\] \[\left[ \because \,x=\frac{a}{3} \right]\] \[=0.48\times {{10}^{-3}}\,J\]
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