A) 1
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
When \[\text{AgN}{{\text{O}}_{\text{3}}}\]is added to \[CoC{{l}_{3}}.xN{{H}_{3}}\]one mole of AgCl is formed hence, the value of \[x\] is 4. \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl\rightleftharpoons {{[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}\] \[+\,\underset{\begin{smallmatrix} \text{can}\,\text{be} \\ \text{precipitated} \end{smallmatrix}}{\mathop{C{{l}^{-}}}}\,\]You need to login to perform this action.
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