A) 1.8
B) 1.0
C) 0.9
D) 0.09
Correct Answer: D
Solution :
The force of limiting friction between the block and trolley \[{{f}_{L}}=\mu R=\mu mg\] \[=0.25\times 2\times 10=5N\] Since, \[F=2N,F<{{f}_{L}}\] So, both will move together with acceleration \[{{a}_{B}}={{a}_{r}}=\frac{2}{20+2}=\frac{1}{11}=0.09m/{{s}^{2}}\]You need to login to perform this action.
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