A) 30 N
B) 26 N
C) 20 N
D) 6 N
Correct Answer: C
Solution :
Tension in the string when it makes angle \[\theta \] with the vertical, \[T=\frac{m{{v}^{2}}}{r}+mg\cos \theta \] When the string is horizontal, \[\theta ={{90}^{o}}\] Here, m = 0.6 kg, r = 0.75 m, v = 5 m/ s Hence, \[T=\frac{m{{v}^{2}}}{r}+mg\times 0=\frac{m{{v}^{2}}}{r}\] \[\therefore \] \[T=\frac{0.6\times {{(5)}^{2}}}{0.75}=20\,N\]You need to login to perform this action.
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