question_answer

The equivalent capacity between the points X and V in the circuit with C = 1 \[\mu \]F is

A)  2\[\mu \]F                                        

B)  3\[\mu \]F

C)   1\[\mu \]F                                       

D)  0.5 \[\mu \]F

Correct Answer: A

Solution :

                 The circuit is shown in the figure. As points a and b are at same potential, so no charge flows through ab. Now two remaining capacitors are in parallel, Hence \[{{C}_{eq}}=C+C=2C\] \[=2\times 1=2\mu F\]