The equivalent capacity between the points X and V in the circuit with C = 1 \[\mu \]F is
A) 2\[\mu \]F
B) 3\[\mu \]F
C) 1\[\mu \]F
D) 0.5 \[\mu \]F
Correct Answer:
A
Solution :
The circuit is shown in the figure. As points a and b are at same potential, so no charge flows through ab. Now two remaining capacitors are in parallel, Hence \[{{C}_{eq}}=C+C=2C\] \[=2\times 1=2\mu F\]