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EAMCET Medical EAMCET Medical Solved Paper-2007

  • question_answer
    The emf induced in a secondary coil is 20000 V when the current breaks in the primary coil. The mutual inductance is 5H and the current reaches to zero in \[{{10}^{-4}}s\]in the primary. The maximum current in the primary before it breaks is

    A)  0.1 A                                    

    B)  0.4 A

    C)   0.6 A                                   

    D)  0.8 A

    Correct Answer: B

    Solution :

                    \[e=\frac{M{{i}_{\max }}}{t}\] or            \[20000=5\times \frac{{{i}_{\max }}}{{{10}^{-4}}}\] or            \[{{i}_{\max }}=\frac{20000\times {{10}^{-4}}}{5}=0.4A\]


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