EAMCET Medical EAMCET Medical Solved Paper-2007

  • question_answer
    The velocity of the most energetic electrons emitted from a metallic surface is doubled when the frequency v of the incident radiation is doubled. The work function of this metal is

    A)   \[\frac{hv}{4}\]                              

    B)  \[\frac{hv}{3}\]

    C)  \[\frac{hv}{2}\]                                               

    D)  \[\frac{2hv}{3}\]

    Correct Answer: D

    Solution :

                     \[\frac{\frac{1}{2}m{{v}^{2}}}{\frac{1}{2}m{{v}^{2}}}=\frac{hv-\text{o }\!\!|\!\!\text{ }}{h(2v)-\text{o }\!\!|\!\!\text{ }}\] or            \[\frac{1}{4}=\frac{hv-\text{o }\!\!|\!\!\text{ }}{2hv-\text{o }\!\!|\!\!\text{ }}\] or            \[\text{o }\!\!|\!\!\text{ =}\frac{2hv}{3}\]


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