A) 1 : 2\[\sqrt{2}\]
B) 2 : 1
C) 2\[\sqrt{2}\]: 1
D) 4 : 1
Correct Answer: C
Solution :
\[\lambda =\frac{h}{\sqrt{2mqV}}\] or \[\lambda \propto \frac{1}{\sqrt{mq}}\] or \[\frac{{{\lambda }_{p}}}{{{\lambda }_{\alpha }}}=\sqrt{\frac{{{m}_{\alpha }}{{q}_{\alpha }}}{{{m}_{p}}{{q}_{p}}}}\] or \[\frac{{{\lambda }_{p}}}{{{\lambda }_{a}}}=\sqrt{\frac{4{{m}_{p}}\times 2{{q}_{p}}}{{{m}_{p}}\times {{q}_{p}}}}\sqrt{8}=2\sqrt{2}\] or \[{{\lambda }_{p}}:{{\lambda }_{\alpha }}=2\sqrt{2}:1\]
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