EAMCET Medical EAMCET Medical Solved Paper-2007

  • question_answer
    Calculate the difference between \[\Delta E\]and\[\Delta H\]  for the following reaction at \[\text{27}{{\,}^{\text{o}}}\text{C}\] (in kcal)  \[C(graphite)+{{H}_{2}}(g)\xrightarrow{{}}C{{H}_{4}}(g)\]

    A)  \[-\text{ }0.6\]                                

    B)  \[-\text{ }1.2\]

    C)  \[+\text{ }0.6\]               

    D)  \[+\text{ }1.2\]

    Correct Answer: C

    Solution :

                     \[C(graphite)+2{{H}_{2}}(g)\xrightarrow{{}}C{{H}_{4}}(g)\] \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] \[\Delta {{n}_{g}}=1-2=-1\] \[\Delta E-\Delta H=-(-1)\times 2\times 300\] \[=600\,cal\] \[=0.6\,\text{Kcal}\]


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