EAMCET Medical EAMCET Medical Solved Paper-2007

  • question_answer
    What is the wave number of 4th  line in Balmer series of hydrogen spectrum? \[(R=1,09,677\,c{{m}^{-1}})\]

    A)  \[24,630\text{ }c{{m}^{-1}}\]   

    B)  \[~24,360\text{ }c{{m}^{-1}}\]

    C)  \[24,730\,\,c{{m}^{-1}}\]            

    D)  \[24,372\,c{{m}^{-1}}\]

    Correct Answer: D

    Solution :

                     \[\bar{v}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For Balmer series \[{{n}_{1}}=2\]and for 4th  line in  Balmer series \[{{n}_{2}}=6\] \[\because \]     \[R=109677\,c{{m}^{-1}}\]                 \[\bar{v}=109677\left( \frac{1}{4}-\frac{1}{36} \right)\] \[=109677\left( \frac{1}{4}-\frac{1}{36} \right)\] \[\bar{v}=24,372\,c{{m}^{-1}}\]


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