A) 1.41
B) 2.14
C) 2.41
D) 3.14
Correct Answer: B
Solution :
\[\therefore \] \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] or \[490-420=\frac{1}{2\times l}\sqrt{\frac{3.6\times {{10}^{2}}}{0.004}}\] or \[70=\frac{1}{2l}\times 300\] or \[l=\frac{300}{2\times 70}=2.14\,m\]You need to login to perform this action.
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