A) 2\[\mu \]F
B) 3\[\mu \]F
C) 1\[\mu \]F
D) 0.5 \[\mu \]F
Correct Answer: A
Solution :
The circuit is shown in the figure. As points a and b are at same potential, so no charge flows through ab. Now two remaining capacitors are in parallel, Hence \[{{C}_{eq}}=C+C=2C\] \[=2\times 1=2\mu F\]You need to login to perform this action.
You will be redirected in
3 sec