A) \[270{}^\circ C\]
B) \[510{}^\circ C\]
C) \[285{}^\circ C\]
D)
Correct Answer: D
Solution :
Neutral temperature \[{{T}_{n}}=\frac{{{T}_{i}}+{{T}_{0}}}{2}=\frac{540+30}{2}=285{{\,}^{o}}C\] \[240{}^\circ C\]You need to login to perform this action.
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