A) \[C{{H}_{3}}COONa,\text{ }C{{H}_{3}}OC{{H}_{3}}\]
B) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}},{{C}_{2}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}\]
C) \[{{C}_{2}}{{H}_{5}}ONa,{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]
D) \[~{{C}_{2}}{{H}_{5}}OH,{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} sodium \\ ethoxide \\ \,\,\,\,\,\,(A) \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}ONa}}\,+\underset{\begin{smallmatrix} ethyl \\ iodide \end{smallmatrix}}{\mathop{I{{C}_{2}}{{H}_{5}}}}\,\xrightarrow[synthesis]{Williamsons}\] \[\underset{\begin{smallmatrix} diethyl\,ether \\ \,\,\,\,\,\,\,\,\,\,\,(B) \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}}}\,+NaI\]
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