A) more by \[KMn{{O}_{4}}\]
B) more by \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]
C) equal in both the cases
D) cannot be determined
Correct Answer: B
Solution :
\[\overset{+7-}{\mathop{M}}\,nO_{4}^{-}5{{e}^{-}}\xrightarrow{{}}M{{n}^{2+}}\]\[\overset{+6}{\mathop{C}}\,{{r}_{2}}O_{7}^{2-}+6{{e}^{-}}\xrightarrow{{}}2C{{r}^{3+}}\]Equal volumes of \[\text{1}\,\text{M}\,\text{KMn}{{\text{O}}_{\text{4}}}\] and \[\text{1}\,\text{M}\,{{\text{K}}_{\text{2}}}\text{C}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}\] have equal number of moles of \[\text{KMn}{{\text{O}}_{\text{4}}}\] and \[{{\text{K}}_{\text{2}}}\text{C}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}\text{.}\]As 1 mole of \[\text{KMn}{{\text{O}}_{\text{4}}}\]accept 5 moles of electrons and 1 mole of \[{{\text{K}}_{\text{2}}}\text{C}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}\text{.}\]accepts 6 moles of electrons. \[{{\text{K}}_{\text{2}}}\text{C}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}\text{.}\]will oxidise more \[\text{F}{{\text{e}}^{\text{2+}}}\]to \[\text{F}{{\text{e}}^{\text{3+}}}.\]
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