A) \[-72\text{ kcal}\]
B) \[-\text{ }28\text{ kcal}\]
C) \[+\text{ }28\text{ kcal}\]
D) \[\text{+ 72 kcal}\]
Correct Answer: D
Solution :
\[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)+22kcal\] \[\because \]The activation energy for the forward reaction = 50 kcal \[\therefore \] The activation energy for the backward reaction = 50 + 22 =72 kcal.
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