EAMCET Medical EAMCET Medical Solved Paper-2007

  • question_answer
    Ethyl chloride on reduction with \[\text{LiAl}{{\text{H}}_{\text{4}}}\] gives compound X as important product. X on chlorination with one mole of \[\text{C}{{\text{l}}_{2}}\]in the presence of light at ordinary temperature   gives Y What is Y?

    A)  \[{{C}_{2}}{{H}_{6}}\]                   

    B)  \[{{C}_{2}}{{H}_{4}}\]

    C)  \[{{C}_{2}}{{H}_{5}}Cl\]               

    D)  \[{{C}_{2}}{{H}_{5}}OH\]

    Correct Answer: C

    Solution :

                     \[\underset{\text{ethyl}\,\text{chloride}}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,+2H\xrightarrow{\text{LiAl}{{\text{H}}_{\text{4}}}}\underset{\begin{smallmatrix}  \text{ethane} \\  \,\,\,\,\,\text{(X)} \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{6}}}}\,\] \[\xrightarrow[\begin{smallmatrix}  \text{chlorination} \\  \text{hv} \end{smallmatrix}]{\text{C}{{\text{l}}_{\text{2}}}}\underset{\begin{smallmatrix}  \text{ethyl}\,\text{chloride} \\  \,\,\,\,\,\,\,\,\,\,\text{(Y)} \end{smallmatrix}}{\mathop{{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{Cl}}}\,\]


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