EAMCET Medical EAMCET Medical Solved Paper-2007

  • question_answer
    A sphere of mass m moving with constant velocity\[\mu \], collides with another stationary sphere of same mass. If e is the coefficient of restitution, the ratio of the final velocities of the first and second spheres is

    A)  \[\frac{1+e}{1-e}\]                                        

    B)  \[\frac{1-e}{1+e}\]

    C)   \[\frac{e}{1-e}\]                            

    D)  \[\frac{1+e}{e}\]

    Correct Answer: B

    Solution :

                     Let \[{{v}_{1}},{{v}_{2}}\]be the final velocities of the two spheres. Applying the law of conservation of linear momentum \[mu=m({{v}_{1}}+{{v}_{2}})\]                 or            \[{{v}_{1}}+{{v}_{2}}=u\]                                              ?(i) Again the coefficient of restitution is given by \[e=\frac{{{v}_{2}}-{{v}_{1}}}{u}\]                 or            \[{{v}_{2}}-{{v}_{1}}=eu\]                                            ?(ii) Solving Eqs. (i) and (ii), we get \[{{v}_{1}}=\frac{u}{2}(1-e),{{v}_{2}}=\frac{u}{2}(1+e)\] Therefore,    \[\frac{{{v}_{1}}}{{{v}_{2}}}=\left( \frac{1-e}{1+e} \right)\]


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