A) \[S{{O}_{2}}\]
B) \[O{{F}_{2}}\]
C) \[SC{{l}_{4}}\]
D) \[S{{O}_{3}}\]
Correct Answer: B
Solution :
\[\text{O}{{\text{F}}_{\text{2}}}\]dissolves in water but does not give any oxyacid solution. While S\[\text{S}{{\text{O}}_{\text{2}}}\text{,SC}{{\text{l}}_{\text{4}}}\text{.}\] and \[\text{S}{{\text{O}}_{3}}\]give oxyacid solution in water. \[S{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}\underset{\text{sulphurous }\,\text{acid}}{\mathop{{{H}_{2}}S{{O}_{3}}}}\,\] \[SC{{l}_{4}}+3{{H}_{2}}O\xrightarrow{{}}\underset{\text{sulphrous}\,\text{acid}}{\mathop{{{H}_{2}}S{{O}_{3}}}}\,+4HCl\] \[S{{O}_{3}}+{{H}_{2}}O\xrightarrow{{}}\underset{\text{sulphurous}\,\text{acid}}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\]
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