A) \[\text{S}{{\text{O}}_{\text{2}}}\] and \[\text{C}{{\text{l}}_{2}}\]
B) CO and \[\text{C}{{\text{l}}_{\text{2}}}\]
C) \[\text{N}{{\text{H}}_{\text{3}}}\]and \[\text{S}{{\text{O}}_{2}}\]
D) \[{{H}_{2}}S\]and \[B{{r}_{2}}\]
Correct Answer: A
Solution :
The bleaching action of \[\text{S}{{\text{O}}_{\text{2}}}\] is due to reduction while the bleaching action of \[\text{C}{{\text{l}}_{\text{2}}}\] is due to oxidation.
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