A) RT log 4
B) RT log 2
C) RT log 1
D) RT log 3
Correct Answer: B
Solution :
Work done W under isothermal change is given by \[W=RT\times n\,\,lo{{g}_{10}}\left( \frac{{{V}_{f}}}{{{V}_{i}}} \right)\]where \[{{V}_{i}}\]and \[{{V}_{f}}\]are the "initial and final volumes of the gas under isothermal change. \[\therefore \] \[W=RT\times 1\times {{\log }_{10}}\left( \frac{2V}{V} \right)\] \[(\because \,n=1,\,{{V}_{i}}=V,\,{{V}_{f}}=2V)\] \[=RT{{\log }_{10}}(2)\]
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