A) 300
B) 200
C) 100/3
D) 200/3
Correct Answer: A
Solution :
We know that, \[H=\frac{{{V}^{2}}}{R}.\] For the same potential difference, the heat produced per second \[H\propto \frac{1}{R}\] One part of the heater coil has a resistance R/3. Hence, \[\frac{{{H}_{2}}}{{{H}_{1}}}=\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{R}{R/3}\] \[\Rightarrow \] \[\frac{{{H}_{2}}}{100}=\frac{3R}{R}\] \[\Rightarrow \]\[{{H}_{2}}=3\times 100=300\,cal.\]You need to login to perform this action.
You will be redirected in
3 sec