question_answer

The correct order of dipole moments for \[\text{N}{{\text{H}}_{\text{3}}}\text{,}{{\text{H}}_{\text{2}}}\text{O}\] and \[\text{C}{{\text{O}}_{2}}\] molecules is

A)  \[NH3>{{H}_{2}}O>C{{O}_{2}}\]

B)  \[C{{O}_{2}}>N{{H}_{3}}>{{H}_{2}}O\]

C)  \[{{H}_{2}}O>C{{O}_{2}}>N{{H}_{3}}\]

D)  \[{{H}_{2}}O>N{{H}_{3}}>C{{O}_{2}}\]

Correct Answer: D

Solution :

               

	(due to regular geometry)
	(due to presence of two lone pair of electrons \[\mu \ne 0\])
	(due to presence of one lone pair of electron\[\mu \ne 0\] )

Greater the number of lone pair of electrons, more will be the dipole moment of the molecule. Hence, the order of dipole moment is\[{{H}_{2}}O>N{{H}_{3}}>C{{O}_{2}}\]