A) \[0.308\]
B) \[0.427\]
C) \[-0.308\]
D) \[0.337\]
Correct Answer: B
Solution :
\[\underset{(1\,atm)}{\mathop{(Pt){{H}_{2}}}}\,\left| {{\underset{(0.01\,M)}{\mathop{H}}\,}^{+}} \right|\left| \underset{(0.1\,M)}{\mathop{C{{u}^{2+}}}}\, \right|Cu\] For the above cell, the cell reaction is \[{{H}_{2}}+C{{u}^{2+}}\xrightarrow{{}}2{{H}^{+}}+Cu\] According to the Nemst equation \[{{E}_{cell}}=E_{C{{u}^{2+}}/Cu}^{o}-\frac{0.0591}{n}\log \frac{{{[{{H}^{+}}]}^{2}}}{[C{{u}^{2+}}]}\] \[=0.337-\frac{0.0591}{2}\log \frac{{{(0.01)}^{2}}}{(0.1)}\] \[=0.337-0.02955\log {{10}^{-3}}\] \[=0.337+0.08865\] \[=0.42565\approx 0.427\]
You need to login to perform this action.
You will be redirected in
3 sec
